2x^2-8x=192

Solution for 2x^2-8x=192 equation:

2x^2-8x=192

We move all terms to the left:

2x^2-8x-(192)=0

a = 2; b = -8; c = -192;
Δ = b2-4ac
Δ = -82-4·2·(-192)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-40}{2*2}=\frac{-32}{4}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+40}{2*2}=\frac{48}{4}
=12
$